Parabola



A parabola (plural parabolas or parabolae, adjective parabolic, from παραβολή) is a two-dimensional, mirror-symmetrical curve, which is approximately U-shaped when oriented as shown in the diagram, but which can be in any orientation in its plane. It fits any of several superficially different mathematical descriptions which can all be proved to define curves of exactly the same shape.

One description of a parabola involves a point (the focus) and a line (the directrix). The focus does not lie on the directrix. The parabola is the locus of points in that plane that are equidistant from both the directrix and the focus. Another description of a parabola is as a conic section, created from the intersection of a right circular conical surface and a plane which is parallel to another plane which is tangential to the conical surface. A third description is algebraic. A parabola is a graph of a quadratic function, such as $$y=x^2.$$

The line perpendicular to the directrix and passing through the focus (that is, the line that splits the parabola through the middle) is called the "axis of symmetry". The point on the axis of symmetry that intersects the parabola is called the "vertex", and it is the point where the curvature is greatest. The distance between the vertex and the focus, measured along the axis of symmetry, is the "focal length". The "latus rectum" is the chord of the parabola which is parallel to the directrix and passes through the focus. Parabolas can open up, down, left, right, or in some other arbitrary direction. Any parabola can be repositioned and rescaled to fit exactly on any other parabola — that is, all parabolas are geometrically similar.

Parabolas have the property that, if they are made of material that reflects light, then light which enters a parabola travelling parallel to its axis of symmetry is reflected to its focus, regardless of where on the parabola the reflection occurs. Conversely, light that originates from a point source at the focus is reflected ("collimated") into a parallel beam, leaving the parabola parallel to the axis of symmetry. The same effects occur with sound and other forms of energy. This reflective property is the basis of many practical uses of parabolas.

The parabola has many important applications, from a parabolic antenna or parabolic microphone to automobile headlight reflectors to the design of ballistic missiles. They are frequently used in physics, engineering, and many other areas.

Strictly, the adjective parabolic should be applied only to things that are shaped as a parabola, which is a two-dimensional shape. However, as shown in the last paragraph, the same adjective is commonly used for three-dimensional objects, such as parabolic reflectors, which are really paraboloids. Sometimes, the noun parabola is also used to refer to these objects. Though not perfectly correct, this usage is generally understood.











History


The earliest known work on conic sections was by Menaechmus in the fourth century BC. He discovered a way to solve the problem of doubling the cube using parabolae. (The solution, however, does not meet the requirements imposed by compass and straightedge construction.) The area enclosed by a parabola and a line segment, the so-called "parabola segment", was computed by Archimedes via the method of exhaustion in the third century BC, in his The Quadrature of the Parabola. The name "parabola" is due to Apollonius, who discovered many properties of conic sections. It means "application", referring to "application of areas" concept, that has a connection with this curve, as Apollonius had proved. The focus–directrix property of the parabola and other conics is due to Pappus.

Galileo showed that the path of a projectile follows a parabola, a consequence of uniform acceleration due to gravity.

The idea that a parabolic reflector could produce an image was already well known before the invention of the reflecting telescope. Designs were proposed in the early to mid seventeenth century by many mathematicians including René Descartes, Marin Mersenne, and James Gregory. When Isaac Newton built the first reflecting telescope in 1668 he skipped using a parabolic mirror because of the difficulty of fabrication, opting for a spherical mirror. Parabolic mirrors are used in most modern reflecting telescopes and in satellite dishes and radar receivers.

Equation in Cartesian coordinates
Let the directrix be the line x = −p and let the focus be the point (p, 0). If (x, y) is a point on the parabola then, by Pappus' definition of a parabola, it is the same distance from the directrix as the focus; in other words:


 * $$x+p=\sqrt{(x-p)^2+y^2}. $$

Squaring both sides and simplifying produces


 * $$y^2 = 4px\ $$

as the equation of the parabola. By interchanging the roles of x and y one obtains the corresponding equation of a parabola with a vertical axis as


 * $$x^2 = 4py.\ $$

The equation can be generalized to allow the vertex to be at a point other than the origin by defining the vertex as the point (h, k). The equation of a parabola with a vertical axis then becomes


 * $$(x-h)^{2}=4p(y-k).\,$$

The last equation can be rewritten


 * $$y=ax^2+bx+c\,$$

so the graph of any function which is a polynomial of degree 2 in x is a parabola with a vertical axis.

More generally, a parabola is a curve in the Cartesian plane defined by an irreducible equation — one that does not factor as a product of two not necessarily distinct linear equations — of the general conic form


 * $$ A x^{2} + B xy + C y^{2} + D x + E y + F = 0 \,$$

with the parabola restriction that


 * $$B^{2} = 4 AC,\,$$

where all of the coefficients are real and where A and C  are not both zero. The equation is irreducible if and only if the determinant of the 3×3 matrix


 * $$\begin{bmatrix}

A & B/2 & D/2 \\

B/2 & C & E/2 \\

D/2 & E/2 & F

\end{bmatrix}.$$

is non-zero: that is, if (AC − B2/4)F + BED/4 − CD2/4 − AE2/4 ≠ 0. The reducible case, also called the degenerate case, gives a pair of parallel lines, possibly real, possibly imaginary, and possibly coinciding with each other.

Conic section and quadratic form
The diagram represents a cone with its axis vertical. The point A is its apex. A horizontal cross-section of the cone passes through the points B, E, C, and D. This cross-section is circular, but appears elliptical when viewed obliquely, as is shown in the diagram. An inclined cross-section of the cone, shown in pink, is inclined from the vertical by the same angle, θ, as the side of the cone. According to the definition of a parabola as a conic section, the boundary of this pink cross-section, EPD, is a parabola. The cone also has another horizontal cross-section, which passes through the vertex, P, of the parabola, and is also circular, with a radius which we will call r. Its centre is V, and $\overline{AV}$ is a diameter. The chord $\overline{PK}$ is a diameter of the lower circle, and passes through the point M, which is the midpoint of the chord $\overline{BC}$. Let us call the lengths of the line segments $\overline{ED}$ and $\overline{EM}$ x, and the length of $\overline{DM}$ y.

Thus:


 * $$BM=2y\sin{\theta}.$$  (The triangle BPM is isosceles.)


 * $$CM=2r.$$  (PMCK is a parallelogram.)

Using the intersecting chords theorem on the chords BC and DE, we get:


 * $$EM \cdot DM=BM \cdot CM$$

Substituting:


 * $$x^2=4ry\sin{\theta}$$

Rearranging:


 * $$y=\frac{x^2}{4r\sin{\theta}}$$

For any given cone and parabola, r and θ are constants, but x and y are variables which depend on the arbitrary height at which the horizontal cross-section BECD is made. This last equation is a simple quadratic one which describes how x and y are related to each other, and therefore defines the shape of the parabolic curve. This shows that the definition of a parabola as a conic section implies its definition as the graph of a quadratic function. Both definitions produce curves of exactly the same shape.

Focal length
It is proved below that if a parabola has an equation of the form y = ax, where a is a constant, then $$a=\frac{1}{4f},$$ where f is its focal length. Comparing this with the last equation above shows that the focal length of the above parabola is r sin θ.

Position of the focus
If a line is perpendicular to the plane of the parabola and passes through the centre, V, of the horizontal cross-section of the cone passing through P, then the point where this line intersects the plane of the parabola is the focus of the parabola, which is marked F on the diagram. Angle VPF is complementary to θ, and angle PVF is complementary to angle VPF, therefore angle PVF is θ. Since the length of $\overline{PM}$ is r, this construction correctly places the focus on the axis of symmetry of the parabola, at a distance r sin θ from its vertex.

Other geometric definitions
A parabola may also be characterized as a conic section with an eccentricity of 1. As a consequence of this, all parabolae are similar, meaning that while they can be different sizes, they are all the same shape. A parabola can also be obtained as the limit of a sequence of ellipses where one focus is kept fixed as the other is allowed to move arbitrarily far away in one direction. In this sense, a parabola may be considered an ellipse that has one focus at infinity. The parabola is an inverse transform of a cardioid.

A parabola has a single axis of reflective symmetry, which passes through its focus and is perpendicular to its directrix. The point of intersection of this axis and the parabola is called the vertex. A parabola spun about this axis in three dimensions traces out a shape known as a paraboloid of revolution.

The parabola is found in numerous situations in the physical world (see below).

Cartesian
In the following equations $$h$$ and $$k$$ are the coordinates of the vertex, $$(h,k)$$, of the parabola and $$p$$ is the distance from the vertex to the focus and the vertex to the directrix.

Vertical axis of symmetry

 * $$(x - h)^2 = 4p(y - k) \,$$


 * $$y =\frac{(x-h)^2}{4p}+k\,$$


 * $$y = ax^2 + bx + c \,$$

where


 * $$a = \frac{1}{4p}; \ \ b = \frac{-h}{2p}; \ \ c = \frac{h^2}{4p} + k; \ \ $$


 * $$h = \frac{-b}{2a}; \ \ k = \frac{4ac - b^2}{4a}$$.

Parametric form:


 * $$x(t) = 2pt + h; \ \ y(t) = pt^2 + k \, $$

Horizontal axis of symmetry

 * $$(y - k)^2 = 4p(x - h) \,$$


 * $$x =\frac{(y - k)^2}{4p} + h;\ \,$$


 * $$x = ay^2 + by + c \,$$

where


 * $$a = \frac{1}{4p}; \ \ b = \frac{-k}{2p}; \ \ c = \frac{k^2}{4p} + h; \ \ $$


 * $$h = \frac{4ac - b^2}{4a}; \ \ k = \frac{-b}{2a}$$.

Parametric form:


 * $$x(t) = pt^2 + h; \ \ y(t) = 2pt + k \, $$

General parabola
The general form for a parabola is


 * $$(\alpha x+\beta y)^2 + \gamma x + \delta y + \epsilon = 0 \,$$

This result is derived from the general conic equation given below:


 * $$Ax^2 +Bxy + Cy^2 + Dx + Ey + F = 0 \, $$

and the fact that, for a parabola,


 * $$B^2=4AC \,$$.

The equation for a general parabola with a focus point F(u, v), and a directrix in the form


 * $$ax+by+c=0 \,$$

is


 * $$\frac{\left(ax+by+c\right)^2}{{a}^{2}+{b}^{2}}=\left(x-u\right)^2+\left(y-v\right)^2 \,$$

Latus rectum, semilatus rectum, and polar coordinates
In polar coordinates, a parabola with the focus at the origin and the directrix parallel to the y-axis, is given by the equation


 * $$r (1 + \cos \theta) = l \,$$

where l is the semilatus rectum: the distance from the focus to the parabola itself, measured along a line perpendicular to the axis of symmetry. Note that this equals the perpendicular distance from the focus to the directrix, and is twice the focal length, which is the distance from the focus to the vertex of the parabola.

The latus rectum is the chord that passes through the focus and is perpendicular to the axis of symmetry. It has a length of 2l.

Gauss-mapped form
A Gauss-mapped form:

$$(\tan^2\phi,2\tan\phi)$$

has normal

$$(\cos\phi,\sin\phi)$$.

Proof of the reflective property


The reflective property states that, if a parabola can reflect light, then light which enters it travelling parallel to the axis of symmetry is reflected to the focus. This is derived from the wave nature of light in the caption to a diagram near the top of this article. This derivation is valid, but may not be satisfying to readers who would prefer a mathematical approach. In the following proof, the fact that every point on the parabola is equidistant from the focus and from the directrix is taken as axiomatic.

Consider the parabola $$y=x^2.$$ Since all parabolas are similar, this simple case represents all others. The right-hand side of the diagram shows part of this parabola.

Construction and definitions

The point E is an arbitrary point on the parabola, with coordinates $$(x,x^2).$$ The focus is F, the vertex is A (the origin), and the line FA (the y-axis) is the axis of symmetry. The line EC is parallel to the axis of symmetry, and intersects the x-axis at D. The point C is located on the directrix (which is not shown, to minimize clutter). The point B is the midpoint of the line segment FC.

Deductions

Measured along the axis of symmetry, the vertex, A, is equidistant from the focus, F, and from the directrix. Correspondingly, since C is on the directrix, the y-coordinates of F and C are equal in absolute value and opposite in sign. B is the midpoint of FC, so its y-coordinate is zero, so it lies on the x-axis. Its x-coordinate is half that of E, D, and C, i.e. $$\frac.$$ The slope of the line BE is the quotient of the lengths of ED and BD, which is $$\frac{x^2}{\left(\frac{x}{2}\right)},$$ which comes to $$2x.$$

But $$2x$$ is also the slope (first derivative) of the parabola at E. Therefore the line BE is the tangent to the parabola at E.

The distances EF and EC are equal because E is on the parabola, F is the focus and C is on the directrix. Therefore, since B is the midpoint of FC, triangles FEB and CEB are congruent (three sides), which implies that the angles marked $$\alpha$$ are equal. (The angle above E is vertically opposite angle BEC.) This means that a ray of light which enters the parabola and arrives at E travelling parallel to the axis of symmetry will be reflected by the line BE so it travels along the line EF, as shown in red in the diagram (assuming that the lines can somehow reflect light). Since BE is the tangent to the parabola at E, the same reflection will be done by an infinitesimal arc of the parabola at E. Therefore, light that enters the parabola and arrives at E travelling parallel to the axis of symmetry of the parabola is reflected by the parabola toward its focus.

The point E has no special characteristics. This conclusion about reflected light applies to all points on the parabola, as is shown on the left side of the diagram. This is the reflective property.

Other consequences
There are other theorems that can be deduced simply from the above argument.

Tangent bisection property
The above proof, and the accompanying diagram, show that the tangent BE bisects the angle FEC. In other words, the tangent to the parabola at any point bisects the angle between the lines joining the point to the focus, and perpendicularly to the directrix.

Intersection of a tangent and perpendicular from focus


Since triangles FBE and CBE are congruent, FB is perpendicular to the tangent BE. Since B is on the x-axis, which is the tangent to the parabola at its vertex, it follows that the point of intersection between any tangent to a parabola and the perpendicular from the focus to that tangent lies on the line that is tangential to the parabola at its vertex. See animated diagram..

Alternative proofs


The above proofs of the reflective and tangent bisection properties use a line of calculus. For readers who are not comfortable with calculus, the following alternative is presented.

In this diagram, F is the focus of the parabola, and T and U lie on its directrix. P is an arbitrary point on the parabola. PT is perpendicular to the directrix, and the line MP bisects angle FPT. Q is another point on the parabola, with QU perpendicular to the directrix. We know that FP=PT and FQ=QU. Clearly, QT>QU, so QT>FQ. All points on the bisector MP are equidistant from F and T, but Q is closer to F than to T. This means that Q is to the "left" of MP, i.e. on the same side of it as the focus. The same would be true if Q were located anywhere else on the parabola (except at the point P), so the entire parabola, except the point P, is on the focus side of MP. Therefore MP is the tangent to the parabola at P. Since it bisects the angle FPT, this proves the tangent bisection property.

The logic of the last paragraph can be applied to modify the above proof of the reflective property. It effectively proves the line BE to be the tangent to the parabola at E if the angles $$\alpha$$ are equal. The reflective property follows as shown previously.

Two tangent properties related to the latus rectum
Let the line of symmetry intersect the parabola at point Q, and denote the focus as point F and its distance from point Q as f. Let the perpendicular to the line of symmetry, through the focus, intersect the parabola at a point T. Then (1) the distance from F to T is 2f, and (2) a tangent to the parabola at point T intersects the line of symmetry at a 45° angle.

Orthoptic property


If two tangents to a parabola are perpendicular to each other, then they intersect on the directrix. Conversely, two tangents which intersect on the directrix are perpendicular.

Proof

Without loss of generality, consider the parabola $$y=x^2.$$ Suppose that two tangents contact this parabola at the points $$(p,p^2)$$ and $$(q,q^2).$$ Their slopes are $$2p$$ and $$2q,$$ respectively. Thus the equation of the first tangent is of the form $$y=2px+C,$$ where $$C$$ is a constant. In order to make the line pass through $$(p,p^2),$$ the value of $$C$$ must be $$-p^2,$$ so the equation of this tangent is $$y=2px-p^2.$$ Likewise, the equation of the other tangent is $$y=2qx-q^2.$$ At the intersection point of the two tangents, $$2px-p^2=2qx-q^2.$$ Thus $$2x(p-q)=p^2-q^2.$$ Factoring the difference of squares, cancelling, and dividing by 2 gives $$x=\frac{p+q}{2}.$$ Substituting this into one of the equations of the tangents gives an expression for the y-coordinate of the intersection point: $$y=2p\left(\frac{p+q}{2}\right)-p^2.$$ Simplifying this gives $$y=pq.$$

We now use the fact that these tangents are perpendicular. The product of the slopes of perpendicular lines is −1, assuming that both of the slopes are finite. The slopes of our tangents are $$2p$$ and $$2q,$$, so $$(2p)(2q)=-1,$$ so $$pq=-\frac{1}{4}.$$ Thus the y-coordinate of the intersection point of the tangents is given by $$y=-\frac{1}{4}.$$ This is also the equation of the directrix of this parabola, so the two perpendicular tangents intersect on the directrix.

Lambert's theorem
Let three tangents to a parabola form a triangle. Then Lambert's theorem states that the focus of the parabola lies on the circumcircle of the triangle.

Properties proved elsewhere in this article
Click on link to find description and proof.


 * Tangent bisection property


 * Intersection of tangent and perpendicular from focus


 * Tangents at endpoints of chords

Dimensions of parabolas with axes of symmetry parallel to the y-axis
These parabolas have equations of the form $$y=ax^2+bx+c.$$ By interchanging $$x$$ and $$y,$$ the parabolas' axes of symmetry become parallel to the x-axis.

Coordinates of the vertex
The x-coordinate at the vertex is $$x=-\frac{b}{2a}$$, which is found by differentiating the original equation $$y=ax^2+bx+c$$, setting the resulting $$dy/dx=2ax+b$$ equal to zero (a critical point), and solving for $$x$$. Substitute this x-coordinate into the original equation to yield:


 * $$y=a\left (-\frac{b}{2a}\right )^2 + b \left ( -\frac{b}{2a} \right ) + c.$$

Simplifying:


 * $$=\frac{ab^2}{4a^2} -\frac{b^2}{2a} + c$$

Put terms over a common denominator


 * $$=\frac{b^2}{4a} -\frac{2\cdot b^2}{2\cdot 2a} + c\cdot\frac{4a}{4a}$$


 * $$=\frac{-b^2+4ac}{4a}$$


 * $$=-\frac{b^2-4ac}{4a}=-\frac{D}{4a}$$

where $$D$$ is the discriminant, $$(b^2-4ac).$$

Thus, the vertex is at point


 * $$\left (-\frac{b}{2a},-\frac{D}{4a}\right ).$$

Coordinates of the focus
Since the axis of symmetry of this parabola is parallel with the y-axis, the x-coordinates of the focus and the vertex are equal. The coordinates of the vertex are calculated in the preceding section. The x-coordinate of the focus is therefore also $$-\frac{b}{2a}.$$

To find the y-coordinate of the focus, consider the point, P, located on the parabola where the slope is 1, so the tangent to the parabola at P is inclined at 45 degrees to the axis of symmetry. Using the reflective property of a parabola, we know that light which is initially travelling parallel to the axis of symmetry is reflected at P toward the focus. The 45-degree inclination causes the light to be turned 90 degrees by the reflection, so it travels from P to the focus along a line that is perpendicular to the axis of symmetry and to the y-axis. This means that the y-coordinate of P must equal that of the focus.

By differentiating the equation of the parabola and setting the slope to 1, we find the x-coordinate of P:


 * $$y=ax^2+bx+c,$$


 * $$\frac{dy}{dx}=2ax+b=1$$


 * $$\therefore x=\frac{1-b}{2a}$$

Substituting this value of $$x$$ in the equation of the parabola, we find the y-coordinate of P, and also of the focus:


 * $$y=a\left(\frac{1-b}{2a}\right)^2+b\left(\frac{1-b}{2a}\right)+c$$


 * $$=a\left(\frac{1-2b+b^2}{4a^2}\right)+\left(\frac{b-b^2}{2a}\right)+c$$


 * $$=\left(\frac{1-2b+b^2}{4a}\right)+\left(\frac{2b-2b^2}{4a}\right)+c$$


 * $$=\frac{1-b^2}{4a}+c=\frac{1-(b^2-4ac)}{4a}=\frac{1-D}{4a}$$

where $$D$$ is the discriminant, $$(b^2-4ac),$$ as is used in the "Coordinates of the vertex" section.

The focus is therefore the point:


 * $$\left(-\frac{b}{2a},\frac{1-D}{4a}\right)$$

Axis of symmetry, focal length, latus rectum, and directrix
The above coordinates of the focus of a parabola of the form:


 * $$y=ax^2+bx+c$$

can be compared with the coordinates of its vertex, which are derived in the section "Coordinates of the vertex", above, and are:


 * $$\left(\frac{-b}{2a},\frac{-D}{4a}\right)$$

where $$D=b^2-4ac.$$

The axis of symmetry is the line which passes through both the focus and the vertex. In this case, it is vertical, with equation:


 * $$x=-\frac{b}{2a}$$.

The focal length of the parabola is the difference between the y-coordinates of the focus and the vertex:


 * $$f=\left(\frac{1-D}{4a}\right)-\left(\frac{-D}{4a}\right)$$


 * $$=\frac{1}{4a}$$

It is sometimes useful to invert this equation and use it in the form: $$a=\frac{1}{4f}.$$ See the section "Conic section and quadratic form", above.

The point where the slope of the parabola is 1 lies at one end of the latus rectum. The length of the semilatus rectum (half of the latus rectum) is the difference between the x-coordinates of this point, which is considered as P in the above derivation of the coordinates of the focus, and of the focus itself. Thus, the length of the semilatus rectum is:


 * $$\frac{1-b}{2a}+\frac{b}{2a}$$


 * $$=\frac{1}{2a}$$


 * $$=2f$$, where $$f$$ is the focal length.

The total length of the latus rectum is therefore four times the focal length.

Measured along the axis of symmetry, the vertex is the midpoint between the focus and the directrix. Therefore, the equation of the directrix is:


 * $$y=-\frac{D}{4a}-\frac{1}{4a}=-\frac{1+D}{4a}$$

Area enclosed between a parabola and a chord
The area enclosed between a parabola and a chord (see diagram) is two-thirds of the area of a parallelogram which surrounds it. One side of the parallelogram is the chord, and the opposite side is a tangent to the parabola. The slope of the other parallel sides is irrelevant to the area. Often, as here, they are drawn parallel with the parabola's axis of symmetry, but this is arbitrary.

A theorem equivalent to this one, but different in details, was derived by Archimedes in the 3rd Century BCE. He used the areas of triangles, rather than that of the parallelogram. See the article "The Quadrature of the Parabola".

If the chord has length b, and is perpendicular to the parabola's axis of symmetry, and if the perpendicular distance from the parabola's vertex to the chord is h, the parallelogram is a rectangle, with sides of b and h. The area, A, of the parabolic segment enclosed by the parabola and the chord is therefore:


 * $$A=\frac{2}{3}bh$$

This formula can be compared with the area of a triangle: $$\frac{1}{2}bh$$.

In general, the enclosed area can be calculated as follows. First, locate the point on the parabola where its slope equals that of the chord. This can be done with calculus, or by using a line that is parallel with the axis of symmetry of the parabola and passes through the midpoint of the chord. The required point is where this line intersects the parabola. Then, using the formula given in the article "Perpendicular distance", calculate the perpendicular distance from this point to the chord. Multiply this by the length of the chord to get the area of the parallelogram, then by $$\textstyle\frac{2}{3}$$ to get the required enclosed area.

Corollary concerning midpoints and endpoints of chords
A corollary of the above discussion is that if a parabola has several parallel chords, their midpoints all lie on a line which is parallel to the axis of symmetry. If tangents to the parabola are drawn through the endpoints of any of these chords, the two tangents intersect on this same line parallel to the axis of symmetry.

Length of an arc of a parabola
If a point X is located on a parabola which has focal length $$f,$$ and if $$p$$ is the perpendicular distance from X to the axis of symmetry of the parabola, then the lengths of arcs of the parabola which terminate at X can be calculated from $$f$$ and $$p$$ as follows, assuming they are all expressed in the same units.


 * $$h=\frac{p}{2}$$


 * $$q=\sqrt{f^2+h^2}$$


 * $$s=\frac{hq}{f}+f\ln\left(\frac{h+q}{f}\right)$$

This quantity, $$s$$, is the length of the arc between X and the vertex of the parabola.

The length of the arc between X and the symmetrically opposite point on the other side of the parabola is $$2s.$$

The perpendicular distance, $$p$$, can be given a positive or negative sign to indicate on which side of the axis of symmetry X is situated. Reversing the sign of $$p$$ reverses the signs of $$h$$ and $$s$$ without changing their absolute values. If these quantities are signed, the length of the arc between any two points on the parabola is always shown by the difference between their values of $$s.$$ The calculation can be simplified by using the properties of logarithms:


 * $$s_1 - s_2 = \frac{h_1 q_1 - h_2 q_2}{f} +f \ln \left(\frac{h_1 + q_1}{h_2 + q_2}\right)$$

This can be useful, for example, in calculating the size of the material needed to make a parabolic reflector or parabolic trough.

This calculation can be used for a parabola in any orientation. It is not restricted to the situation where the axis of symmetry is parallel to the y-axis.

Mathematical generalizations
In algebraic geometry, the parabola is generalized by the rational normal curves, which have coordinates $$(x,x^2,x^3,\dots,x^n);$$ the standard parabola is the case $$n=2,$$ and the case $$n=3$$ is known as the twisted cubic. A further generalization is given by the Veronese variety, when there is more than one input variable.

In the theory of quadratic forms, the parabola is the graph of the quadratic form $$x^2$$ (or other scalings), while the elliptic paraboloid is the graph of the positive-definite quadratic form $$x^2+y^2$$ (or scalings) and the hyperbolic paraboloid is the graph of the indefinite quadratic form $$x^2-y^2.$$ Generalizations to more variables yield further such objects.

The curves $$y=x^p$$ for other values of p are traditionally referred to as the higher parabolas, and were originally treated implicitly, in the form $$x^p=ky^q$$ for p and q both positive integers, in which form they are seen to be algebraic curves. These correspond to the explicit formula $$y=x^{p/q}$$ for a positive fractional power of x. Negative fractional powers correspond to the implicit equation $$x^py^q=k,$$ and are traditionally referred to as higher hyperbolas. Analytically, x can also be raised to an irrational power (for positive values of x); the analytic properties are analogous to when x is raised to rational powers, but the resulting curve is no longer algebraic, and cannot be analyzed via algebraic geometry.

Parabolae in the physical world
In nature, approximations of parabolae and paraboloids  (such as catenary curves) are found in many diverse situations. The best-known instance of the parabola in the history of physics is the trajectory of a particle or body in motion under the influence of a uniform gravitational field without air resistance (for instance, a baseball flying through the air, neglecting air friction).

The parabolic trajectory of projectiles was discovered experimentally by Galileo in the early 17th century, who performed experiments with balls rolling on inclined planes. He also later proved this mathematically in his book Dialogue Concerning Two New Sciences. For objects extended in space, such as a diver jumping from a diving board, the object itself follows a complex motion as it rotates, but the center of mass of the object nevertheless forms a parabola. As in all cases in the physical world, the trajectory is always an approximation of a parabola. The presence of air resistance, for example, always distorts the shape, although at low speeds, the shape is a good approximation of a parabola. At higher speeds, such as in ballistics, the shape is highly distorted and does not resemble a parabola.

Another hypothetical situation in which parabolae might arise, according to the theories of physics described in the 17th and 18th Centuries by Sir Isaac Newton, is in two-body orbits; for example the path of a small planetoid or other object under the influence of the gravitation of the Sun. Parabolic orbits do not occur in nature; simple orbits most commonly resemble hyperbolas or ellipses. The parabolic orbit is the degenerate intermediate case between those two types of ideal orbit. An object following a parabolic orbit would travel at the exact escape velocity of the object it orbits; objects in elliptical or hyperbolic orbits travel at less or greater than escape velocity, respectively. Long-period comets travel close to the Sun's escape velocity while they are moving through the inner solar system, so their paths are close to being parabolic.

Approximations of parabolae are also found in the shape of the main cables on a simple suspension bridge. The curve of the chains of a suspension bridge is always an intermediate curve between a parabola and a catenary, but in practice the curve is generally nearer to a parabola, and in calculations the second degree parabola is used. Under the influence of a uniform load (such as a horizontal suspended deck), the otherwise catenary-shaped cable is deformed toward a parabola. Unlike an inelastic chain, a freely hanging spring of zero unstressed length takes the shape of a parabola. Suspension-bridge cables are, ideally, purely in tension, without having to carry other, e.g. bending, forces. Similarly, the structures of parabolic arches are purely in compression.

Paraboloids arise in several physical situations as well. The best-known instance is the parabolic reflector, which is a mirror or similar reflective device that concentrates light or other forms of electromagnetic radiation to a common focal point, or conversely, collimates light from a point source at the focus into a parallel beam. The principle of the parabolic reflector may have been discovered in the 3rd century BC by the geometer Archimedes, who, according to a legend of debatable veracity, constructed parabolic mirrors to defend Syracuse against the Roman fleet, by concentrating the sun's rays to set fire to the decks of the Roman ships. The principle was applied to telescopes in the 17th century. Today, paraboloid reflectors can be commonly observed throughout much of the world in microwave and satellite-dish receiving and transmitting antennas.

In parabolic microphones, a parabolic reflector that reflects sound, but not necessarily electromagnetic radiation, is used to focus sound onto a microphone, giving it highly directional performance.

Paraboloids are also observed in the surface of a liquid confined to a container and rotated around the central axis. In this case, the centrifugal force causes the liquid to climb the walls of the container, forming a parabolic surface. This is the principle behind the liquid mirror telescope.

Aircraft used to create a weightless state for purposes of experimentation, such as NASA's "Vomit Comet," follow a vertically parabolic trajectory for brief periods in order to trace the course of an object in free fall, which produces the same effect as zero gravity for most purposes.

In the United States, vertical curves in roads are usually parabolic by design.

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